A mixture problem: 2 parts A at 20% and 3 parts B at 60% yield what overall percentage?

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Multiple Choice

A mixture problem: 2 parts A at 20% and 3 parts B at 60% yield what overall percentage?

Explanation:
When mixing amounts with different concentrations, the overall percentage is found by a weighted average: add up the actual amount of solute contributed by each part and divide by the total amount of mixture. Here, two parts are at 20% and three parts at 60%. Solute from the first part is 2 × 0.20 = 0.40. Solute from the second part is 3 × 0.60 = 1.80. Total solute = 0.40 + 1.80 = 2.20. Total parts = 2 + 3 = 5. Overall percentage = 2.20 / 5 = 0.44, or 44%. This result lies between 20% and 60%, and accounts for the greater share from the 60% portion, so 44% is the correct overall percentage.

When mixing amounts with different concentrations, the overall percentage is found by a weighted average: add up the actual amount of solute contributed by each part and divide by the total amount of mixture.

Here, two parts are at 20% and three parts at 60%. Solute from the first part is 2 × 0.20 = 0.40. Solute from the second part is 3 × 0.60 = 1.80. Total solute = 0.40 + 1.80 = 2.20. Total parts = 2 + 3 = 5. Overall percentage = 2.20 / 5 = 0.44, or 44%.

This result lies between 20% and 60%, and accounts for the greater share from the 60% portion, so 44% is the correct overall percentage.

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